These solutions relate to puzzles found in Issue 04 of the magazine.
Odd sums
The sum of the first $n$ odd numbers is $n^2$ (this can be proved by induction). This means that:
$$\frac{\text{sum of the
first }n\text{ odd numbers}}{\text{sum of the next }n\text{ odd numbers}}=\frac{n^2}{(2n)^2-n^2}\\
=\frac{n^2}{3n^2}=\frac{1}{3}$$
Odd squares
1 and 9 are the only two square numbers whose digits are all odd.
Two lines
The co-ordinates will be (1,gradient+intercept).